A bulb of volume 500 c m 3 is sealed at 3 × 1 0 − 5 mm Hg and 2 7 ∘ C. Find the number of molecules in it in units of 1 0 14 (two decimals).

N = k T P V = 1.38 × 1 0 − 23 × 300 3 × 1 0 − 5 × 133.3 × 5 × 1 0 − 4 = 4.83 × 1 0 14 .

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKinetic Theory of Gases and Gas LawsMedium2 minQB

PhysicsMediumnumerical

A bulb of volume 500 $c m^{3}$ is sealed at $3 \times 1 0^{- 5}$ mm Hg and $2 7^{\circ}$ C. Find the number of molecules in it in units of $1 0^{14}$ (two decimals).

Answer:

4.83

Solution:

$N = \frac{P V}{k T} = \frac{3 \times 1 0 ^{- 5} \times 133.3 \times 5 \times 1 0 ^{- 4}}{1.38 \times 1 0 ^{- 23} \times 300} = 4.83 \times 1 0^{14}$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Kinetic Theory of Gases and Gas Laws

⏱ 2mℹ️ Source: QB

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