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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamicsMedium2 minQB

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A monoatomic gas is taken from A to C as shown in the figure. The temperature of gas at B is 27°C, then the change in internal energy of the gas is

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Answer:

Solution:

$Δ U = \frac{3}{2} (P_{C} V_{C} - P_{A} V_{A}) = \frac{3}{2} (200 \times 1 0^{3} \times 150 \times 1 0^{- 6} - 100 \times 1 0^{3} \times 100 \times 1 0^{- 6})$ .

$= \frac{3}{2} (30 - 10) = 30 J .$

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Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics

⏱ 2mℹ️ Source: QB

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