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Physics - SHM Question with Solution | TestHub

PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediummultiple choice

Two masses $m_{1}$ and $m_{2}$ ( $m_{1} > m_{2}$ ) are suspended by two springs vertically, and the extensions in equilibrium are the same. Both masses are displaced vertically by the same distance and released. $T_{1}$ , $T_{2}$ are their time periods and $E_{1}$ , $E_{2}$ the energies of oscillation. Then:

Options:(select one or more)

Answer:

A, D

Solution:

Equal extensions: $m_{1} g / k_{1} = m_{2} g / k_{2}$ so $m / k$ is equal and $T_{1} = T_{2}$ . $k_{1} > k_{2}$ , so for the same displacement $E = \frac{1}{2} k x^{2}$ gives $E_{1} > E_{2}$ . (A) and (D) state the same thing.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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