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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

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The density ( $ρ$ ) versus temperature ( $T$ ) graph of an ideal gas undergoing a process $A B$ is as shown in Figure 3.88 (a vertical line from $A$ down to $B$ at fixed $T$ ). Choose the incorrect option:

Options:

Answer:

Solution:

$T$ is constant, so the process is isothermal and $Δ U = 0$ , $P_{A} V_{A} = P_{B} V_{B}$ . $ρ$ falls, so $V$ rises, $P$ falls ( $P_{B} < P_{A}$ ) and work is positive. Option B is incorrect. B.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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