How much steam at 100°C is needed to change 30 g of ice at -20°C to water at 30°C if the ice is in a 40 g aluminium can that stays at the temperature of its contents? c A l = 0.22 , c ice = 0.5 ca

Question

How much steam at 100°C is needed to change 30 g of ice at -20°C to water at 30°C if the ice is in a 40 g aluminium can that stays at the temperature of its contents? c A l ​ = 0.22 , c ice ​ = 0.5 cal / ( g ∘ C ) , L f ​ = 80 , L v ​ = 540 cal / g . Give g to two decimals.

TestHub · Accepted Answer

Heat needed: ice warming 300 cal, melting 2400, water warming 900, can 40 ( 0.22 ) ( 50 ) = 440 . Total 4040 cal. Each gram of steam gives 540 + 70 = 610 cal . Mass = 6.62 g .

Physics - Heat & Thermo Question with Solution | TestHub

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