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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

PhysicsMediumsingle choice

A heat flux of 4000 J $s^{- 1}$ is to be passed through a copper rod of length 10 cm and area of cross-section 100 $c m^{2}$ . The thermal conductivity of copper is 400 W $m^{- 1}$ $^{\circ}$ $C^{- 1}$ . The two ends of this rod must be kept at a temperature difference of:

Options:

Answer:

Solution:

$Δ T = \frac{Q l}{K A} = \frac{4000 \times 0.1}{400 \times 0.01} = 10 0^{\circ}$ C. C.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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