The temperature of a perfect black body is 72 7 ∘ C and its area is 0.1 m 2 . If Stefan's constant is 5.67 × 1 0 − 8 W m − 2 K − 4 , then the heat radiated by it in 1 minute is:

P = σ A T 4 = 5.67 × 1 0 − 8 × 0.1 × 1 0 12 = 5670 W. In 60 s: 340200 J = 4.2 340200 = 81000 cal. B.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

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The temperature of a perfect black body is $72 7^{\circ}$ C and its area is 0.1 $m^{2}$ . If Stefan's constant is $5.67 \times 1 0^{- 8}$ W $m^{- 2}$ $K^{- 4}$ , then the heat radiated by it in 1 minute is:

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Solution:

$P = σ A T^{4} = 5.67 \times 1 0^{- 8} \times 0.1 \times 1 0^{12} = 5670$ W. In 60 s: $340200$ J = $\frac{340200}{4.2} = 81000$ cal. B.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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