A rigid container has a hole in its wall. When some air is filled in it at 27°C, weight of air in it is 100 gm. Now the temperature of air inside is increased by Δ T , the weight of air becomes 50 gm.

Question

A rigid container has a hole in its wall. When some air is filled in it at 27°C, weight of air in it is 100 gm. Now the temperature of air inside is increased by Δ T , the weight of air becomes 50 gm. Δ T should be:

TestHub · Accepted Answer

P V = M m ​ RT with P, V constant ⇒ m T = constant: 50 ( 300 + Δ T ) = 100 ( 300 ) ⇒ Δ T = 300 K = 30 0 ∘ C .

Physics - Heat & Thermo Question with Solution | TestHub

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