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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionHard2 minQB

PhysicsHardsingle choice

Liquid tin at its melting point 232°C is poured into a calorimeter of oil; the oil warms from 15.0°C to 28.0°C. Repeating with solid tin at 232°C, the oil warms from 15.0°C to 20.0°C. Specific heat of tin (both states) is 0.23 J/(g °C). Find the latent heat of fusion of tin in J/g. Choose the correct value.

Options:

Answer:

Solution:

Let C be the heat capacity of oil plus calorimeter. Liquid: $m [L + 0.23 (232 - 28)] = 13 C$ . Solid: $m 0.23 (232 - 20) = 5 C$ . Divide: $L + 46.92 = \frac{13}{5} (48.76) = 126.78$ , so $L = 79.86 J /$ g. Option C.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

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