A jar contains gas G 1 at pressure p , volume V and temperature T . Another jar contains gas G 2 at pressure 2 p , volume 2 V and temperature 2 T . What is the ratio of the number of molecules of G 1 to that of G 2 ?

N = k T P V . N 1 ∝ T p V and N 2 ∝ 2 T 2 2 p ⋅ V = 2 T p V . Ratio = 2. B.

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PhysicsHeat & ThermoKinetic Theory of Gases and Gas LawsMedium2 minQB

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A jar contains gas $G_{1}$ at pressure $p$ , volume $V$ and temperature $T$ . Another jar contains gas $G_{2}$ at pressure $2 p$ , volume $\frac{V}{2}$ and temperature $2 T$ . What is the ratio of the number of molecules of $G_{1}$ to that of $G_{2}$ ?

Options:

Answer:

Solution:

$N = \frac{P V}{k T}$ . $N_{1} \propto \frac{p V}{T}$ and

$N_{2} \propto \frac{\frac{2 p \cdot V}{2}}{2 T} = \frac{p V}{2 T}$ . Ratio =

2. B.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Kinetic Theory of Gases and Gas Laws

⏱ 2mℹ️ Source: QB

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