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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGMedium2 minQB

PhysicsMediumsingle choice

A gas molecule of mass M at the surface of the Earth has kinetic energy equivalent to 0°C. If it were to go up straight without colliding with any other molecules, how high it would rise? Assume that the height attained is much less than radius of the earth. ( $k_{B}$ is Boltzmann constant)

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Answer:

Solution:

$KE = \frac{3}{2} k_{B} \times 273 = \frac{819 k _{B}}{2}$ . Rising against gravity: $M g h = \frac{819 k _{B}}{2} \Rightarrow h = \frac{819 k _{B}}{2 M g}$ .

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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