Physics - Heat & Thermo Question with Solution | TestHub

$B=2P$ for $P{V}^2=\text{ constant}$. $B$ against $P$ is a line through the origin (A). $P\propto V^{-2}$, so $B$ falls with $V$ like $V^{-2}$ (B). $TV=\text{ constant}$ and $P\propto T^2$, so $B\propto T^2$, a rising parabola (C). Graph (D) rises with $V$, which is wrong. A, B, C.