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Physics - NLM Question with Solution | TestHub

PhysicsNLMMedium2 minQB

PhysicsMediummultiple choice

For given figure $m_{A}$ is $30 kg m_{B} = m_{C} = 5 kg$ respectively. All contact surfaces are smooth. $(g = 10 m / s^{2})$ . Select the correct statements.

Options:(select one or more)

Answer:

A, C, D

Solution:

$T = (m_{B} + m_{C}) a$

$T = 10 a T + m_{A} a = m_{A} A T = m_{A} (A - a) T = 30 (A - a) \Rightarrow N = m_{C} a m_{C} g - T = m_{C} A 50 - T = 5 A 50 = 10 a + 5 A A + 2 a = 10 4 a = 3 A$

$A + \frac{3 A}{2} = 10 A = 4 a = 3 T = 30 N N = 15 N$

Contact force between B and ground is 380 N.

$N_{G} = 5 g + 30 g + T = 380 N$

Stream:JEESubject:PhysicsTopic:NLM

⏱ 2mℹ️ Source: QB

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