Consider the shown arrangement where the blocks A and B connected by means of a uniform string is being moved vertically up by the force F. Each block weighs 2 kg while the mass of string is 1000 gm.

Question

Consider the shown arrangement where the blocks A and B connected by means of a uniform string is being moved vertically up by the force F. Each block weighs 2 kg while the mass of string is 1000 gm. The tension at bottom of the string equals.

Options:

Answer:

B

Solution:

$100 - 50 = 5 a a = 10 m / s^{2} ↑$

$T - 2 g = 2 a \Rightarrow T = 40 N$

TestHub · Accepted Answer

​ 100 − 50 = 5 a ​ a = 10 m / s 2 ↑ ​ T − 2 g = 2 a ⇒ T = 40 N

Physics - NLM Question with Solution | TestHub

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