Start Free Mock LoginAlready registered? Login here

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferHard2 min

PhysicsHardnumerical

A skater of mass 60 kg stands on blades with a total contact area of $4 \times 1 0^{- 5}$ $m^{2}$ . The melting point of ice falls by 0.0075 K per atmosphere of extra pressure. Find the fall in the melting point in kelvin (two decimals; $g = 9.8$ , 1 atm = $1.013 \times 1 0^{5}$ Pa).

Answer:

1.09

Solution:

$P = \frac{m g}{A} = \frac{60 \times 9.8}{4 \times 1 0 ^{- 5}} = 1.47 \times 1 0^{7}$ Pa = $145$ atm. Fall = $145 \times 0.0075 = 1.09$ K. A thin film of water forms and makes the ice slippery.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

⏱ 2m

Doubts & Discussion

Loading discussions...