Start Free Mock LoginAlready registered? Login here

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGMedium2 minQB

PhysicsMediumsingle choice

Passage / Comprehension

In the cylinder shown in the figure, air is enclosed under the piston. Piston mass M = 60 kg, cross-sectional area of the cylinder S₀ = 20 cm², atmospheric pressure P₀ = 10⁵ Pa. α = 37°. The air temperature is constant, the friction is negligible.

What is the pressure of the enclosed gas?

Options:

Answer:

Solution:

$P_{0} S_{0} + m g = P S_{0} sec 3 7^{\circ} cos 3 7^{\circ} \Rightarrow P = P_{0} + \frac{m g}{S _{0}}$ .

$P = 1 0^{5} + \frac{600}{20 \times 1 0 ^{- 4}} = 4 \times 1 0^{5} Pa .$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...