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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

PhysicsMediumnumerical

How much work must be done adiabatically on one mole of a diatomic gas to increase its rms speed 4 times from 280 K? Give the answer in kJ (one decimal).

Answer:

87.30

Solution:

$v_{r m s} \propto T$ , so $T_{2} = 16 \times 280 = 4480$ K. $W = Δ U = \frac{5}{2} R Δ T = \frac{5}{2} \times 8.314 \times 4200 = 87.3$ kJ.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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