A load attached to the end of a spring and in equilibrium produces 9 cm extension of spring. If the spring is cut into three equal parts and one end of each is fixed at 'O' and other ends ar

Question

A load attached to the end of a spring and in equilibrium produces 9 cm extension of spring. If the spring is cut into three equal parts and one end of each is fixed at 'O' and other ends are attached to the same load, the extension in cm of the combination in equilibrium now is

Options:

Answer:

A

Solution:

$k \times 9 = mg$

$k_{res} = 3 k + 3 k + 3 k = 9 k 9 k \times x = mg$

$\frac{9 k}{9 kx} = \frac{mg}{mg} \Rightarrow x = 1 cm$

TestHub · Accepted Answer

k × 9 = mg ​ k res ​ = 3 k + 3 k + 3 k = 9 k ​ 9 k × x = mg ​ 9 kx 9 k ​ = mg mg ​ ⇒ x = 1 cm

Physics - NLM Question with Solution | TestHub

Options:

Doubts & Discussion