An amount Q of heat is added to a monoatomic ideal gas in a process in which the gas performs a work 2 Q on its surroundings. The molar heat capacity for the process is:

Δ U = Q − 2 Q = 2 Q = n 2 3 R Δ T , so n Δ T = 3 R Q . C = n Δ T Q = 3 R . C.

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PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

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An amount $Q$ of heat is added to a monoatomic ideal gas in a process in which the gas performs a work $\frac{Q}{2}$ on its surroundings. The molar heat capacity for the process is:

Options:

Answer:

Solution:

$Δ U = Q - \frac{Q}{2} = \frac{Q}{2} = n \frac{3}{2} R Δ T$ , so $n Δ T = \frac{Q}{3 R}$ . $C = \frac{Q}{n Δ T} = 3 R$ . C.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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