Physics - NLM Question with Solution | TestHub

$$\begin{array}{rlrl}{\mathrm{f}}_{\mathrm{k}}& =(0.1)\left(4\mathrm{gcos}37^{\circ }\right)& =3.2\mathrm{N}\mathrm{N}& =\left(4\mathrm{gcos}37^{\circ }\right)=32\mathrm{N}\end{array}$$

Net contact force

$$=\sqrt{32^2+(3.2{)}^2}\simeq 32.16\mathrm{N}$$

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$$\begin{array}{rlr}& \tan \theta =\frac{{\mathrm{f}}_{\mathrm{k}}}{\mathrm{N}}={\mathrm{N}}_{\mathrm{k}}& \mathrm{Q}={\tan }^{-1}\left({\mathrm{N}}_{\mathrm{k}}\right)\end{array}$$

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