A point object performs SHM about mean position $x = 25 cm$ , in front of a concave mirror of focal length 10 cm. Position of the particle about the mean position is given $x = 5 sin 9 t$ (in cm).
What is the difference between maximum and minimum distance of image from mirror (in cm).

Question

A point object performs SHM about mean position $x = 25 cm$ , in front of a concave mirror of focal length 10 cm. Position of the particle about the mean position is given $x = 5 sin 9 t$ (in cm).

What is the difference between maximum and minimum distance of image from mirror (in cm).

TestHub · Accepted Answer

Object distance ranges from 20 cm to 30 cm as the particle oscillates about 25 cm.

$v (20) = \frac{20 \times 10}{20 - 10} = 20 cm$ , $v (30) = \frac{30 \times 10}{30 - 10} = 15 cm$

Difference: $20 - 15 = 5 cm$ .

Answer: 5.00

Physics - SHM Question with Solution | TestHub

Doubts & Discussion