Find the ice mass at 0°C that just completely melts when mixed with 300 g water at 40°C in an insulated vessel. Use $L_{f} = 80 cal / g, c_{w} = 1 cal g^{- 1}^{\circ} C^{- 1}$ ; final temperature is $0^{\circ} C$ . Enter grams.
Answer:
150
Solution:
$m_{i} L_{f} = m_{w} c_{w} Δ T$ .
$m_{i} = \frac{300 ( 40 )}{80} = 150 g .$

Question

Find the ice mass at 0°C that just completely melts when mixed with 300 g water at 40°C in an insulated vessel. Use $L_{f} = 80 cal / g, c_{w} = 1 cal g^{- 1}^{\circ} C^{- 1}$ ; final temperature is $0^{\circ} C$ . Enter grams.

Answer:

150

Solution:

$m_{i} L_{f} = m_{w} c_{w} Δ T$ .

$m_{i} = \frac{300 ( 40 )}{80} = 150 g .$

TestHub · Accepted Answer

m i ​ L f ​ = m w ​ c w ​ Δ T . m i ​ = 80 300 ( 40 ) ​ = 150 g .

Physics - Heat & Thermo Question with Solution | TestHub

Doubts & Discussion