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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesEasy2 minQB

PhysicsEasyinteger

For the heating in the previous question (3 mol, constant volume, $20$ K rise, $C_{v} = 5$ cal $m o l^{- 1}$ $K^{- 1}$ ), find the change in internal energy in calories.

Answer:

300

Solution:

At constant volume $W = 0$ , so $Δ U = Q = 3 \times 5 \times 20 = 300$ cal.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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