2 g ice at 0°C is added to 10 g water at 8°C. Use cw = 1 cal / ( g ∘ C ) and Lf = 80 cal / g . Final state is:

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PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

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2 g ice at 0°C is added to 10 g water at 8°C. Use $cw = 1 cal / (g^{\circ} C)$ and $Lf = 80 cal / g$ . Final state is:

Answer:

Solution:

Water releases 80 cal cooling to 0°C, melting 1 g ice. Final 1 g ice + 11 g water at 0°C.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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