A geyser, operating on LPG (liquefied petroleum gas), heats water flowing at the rate of 3.0 litres per minute from 2 7 ∘ C to 7 7 ∘ C. If the heat of combustion of LPG is 4.0 × 1 0 4 J g − 1 , how much fuel is consumed per minute (in grams)?

Water per minute = 3000 g. Q = 3000 × 4.2 × 50 = 6.3 × 1 0 5 J. Fuel = 4 × 1 0 4 6.3 × 1 0 5 = 15.75 g. C.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

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A geyser, operating on LPG (liquefied petroleum gas), heats water flowing at the rate of 3.0 litres per minute from $2 7^{\circ}$ C to $7 7^{\circ}$ C. If the heat of combustion of LPG is $4.0 \times 1 0^{4}$ J $g^{- 1}$ , how much fuel is consumed per minute (in grams)?

Options:

Answer:

Solution:

Water per minute = $3000$ g. $Q = 3000 \times 4.2 \times 50 = 6.3 \times 1 0^{5}$ J. Fuel = $\frac{6.3 \times 1 0 ^{5}}{4 \times 1 0 ^{4}} = 15.75$ g. C.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

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