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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGMedium2 minQB

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A ring shaped tube contains two ideal gases with equal masses and molar masses $M_{1} = 32$ and $M_{2} = 28$ . The gases are separated by one fixed partition P and another movable stopper S which can move freely without friction inside the ring. The angle $α$ is

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Solution:

At equilibrium both gases have same P and T, so $V \propto n : V_{1} : V_{2} = \frac{m}{32} : \frac{m}{28} = 28 : 32 =$ 7 : 8. Larger share: $α = \frac{8}{15} \times 36 0^{\circ} = 19 2^{\circ}$ .

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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