A constant volume air thermometer shows a mercury level difference of 15 cm in melting ice and 48.3 cm in boiling water. In a hot liquid the difference is 35 cm. Find the temperature of the liquid in

Question

A constant volume air thermometer shows a mercury level difference of 15 cm in melting ice and 48.3 cm in boiling water. In a hot liquid the difference is 35 cm. Find the temperature of the liquid in °C (nearest integer).

Answer:

60.00

Solution:

The scale is $(100) / (48.3 - 15)$ degrees per $cm . T = (35 - 15) / (33.3) \times 100 = 6 0^{\circ} C$ .

TestHub · Accepted Answer

The scale is ( 100 ) / ( 48.3 − 15 ) degrees per cm . T = ( 35 − 15 ) / ( 33.3 ) × 100 = 6 0 ∘ C .

Physics - Heat & Thermo Question with Solution | TestHub

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