Start Free Mock LoginAlready registered? Login here

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGMedium2 minQB

PhysicsMediumsingle choice

Gaseous hydrogen contained initially under standard condition in a sealed vessel of 5 litre was cooled by 55 K. The internal energy will change by

Options:

Answer:

Solution:

$n = \frac{P V}{RT} = \frac{1 \times 1 0 ^{5} \times 5 \times 1 0 ^{- 3}}{8.3 \times 300} .Δ U = n C_{V} Δ T = \frac{1 \times 1 0 ^{5} \times 5 \times 1 0 ^{- 3}}{8.3 \times 300} \times \frac{5}{2} \times 8.3 \times 55 \approx$ $\frac{25 \times 55}{6} J \approx 0.23 kJ$ .

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...