The room temperature is 2 0 ∘ C. Water in a container cools from 5 5 ∘ C to 4 5 ∘ C in 8 minutes. How much time will it take in cooling from 4 5 ∘ C to 3 5 ∘ C?

First: 8 10 = k ( 50 − 20 ) , so k = 24 1 . Second: t 10 = 24 1 ( 40 − 20 ) , so t = 12 minutes. B.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

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The room temperature is $2 0^{\circ}$ C. Water in a container cools from $5 5^{\circ}$ C to $4 5^{\circ}$ C in 8 minutes. How much time will it take in cooling from $4 5^{\circ}$ C to $3 5^{\circ}$ C?

Options:

Answer:

Solution:

First: $\frac{10}{8} = k (50 - 20)$ , so $k = \frac{1}{24}$ . Second: $\frac{10}{t} = \frac{1}{24} (40 - 20)$ , so $t = 12$ minutes. B.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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