An ideal diatomic gas ( γ = 1.4 ) is at a pressure of 200 kPa and volume 0.010 m 3 . Find the magnitude of the slope, − d V d P , of the adiabatic curve through this state in units of 1 0 7 Pa m − 3 (two decimals).

Adiabatic: − d V d P = V γ P = 0.010 1.4 × 2 × 1 0 5 = 2.80 × 1 0 7 Pa m − 3 .

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PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

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An ideal diatomic gas ( $γ = 1.4$ ) is at a pressure of 200 kPa and volume 0.010 $m^{3}$ . Find the magnitude of the slope, $- \frac{d P}{d V}$ , of the adiabatic curve through this state in units of $1 0^{7}$ Pa $m^{- 3}$ (two decimals).

Answer:

2.80

Solution:

Adiabatic: $- \frac{d P}{d V} = \frac{γ P}{V} = \frac{1.4 \times 2 \times 1 0 ^{5}}{0.010} = 2.80 \times 1 0^{7}$ Pa $m^{- 3}$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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