A pendulum of length 0.9 m has a nail below its pivot at 9 8 of the length. Find the time for the bob to return to its release point for the first time, in s ( g = 9.8 ).

Remaining length l /9 . Time = π l / g + π l /9 g = 3 4 π l / g = 1.27 s.

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PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumnumerical

A pendulum of length 0.9 m has a nail below its pivot at $\frac{8}{9}$ of the length. Find the time for the bob to return to its release point for the first time, in s ( $g = 9.8$ ).

Answer:

1.27

Solution:

Remaining length $l /9$ . Time = $π l / g + π l /9 g = \frac{4 π}{3} l / g = 1.27$ s.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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