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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

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Heat energy absorbed by a system going through the cyclic process shown in Figure 3.71 (a circle on a $P$ - $V$ diagram, $V$ from 10 to 30 litres and $P$ from 10 to 30 kPa) is:

Options:

Answer:

Solution:

Net heat equals net work, which is the area of the circle. $A = π r^{2}$ with $r = 10$ L = $1 0^{- 2}$ $m^{3}$ on one axis and $r = 10$ kPa = $1 0^{4}$ Pa on the other, so $A = π \times 1 0^{- 2} \times 1 0^{4} = 1 0^{2} π$ J. C.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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