Four glass columns A, B, C, D are joined as in the standard hot-cold arrangement. B and C are each 60 cm high. A and C are kept at 95°C; B and D at 5°C. A and D are open at the top. The liquid stands

Question

Four glass columns A, B, C, D are joined as in the standard hot-cold arrangement. B and C are each 60 cm high. A and C are kept at 95°C; B and D at 5°C. A and D are open at the top. The liquid stands 51.5 cm high in A and 50 cm in D. If the coefficient of cubical expansion of the liquid is P × 1 0 − 4 per °C, then find P.

TestHub · Accepted Answer

Pressure balance round the loop: ρ 95 ​ ( h A ​ + h C ​ ) = ρ 5 ​ ( h D ​ + h B ​ ) , so ρ 95 ​ ρ 5 ​ ​ = 110 111.5 ​ = 1.013636 = 1 + 5 γ 1 + 95 γ ​ . Then γ = 95 − 5 ( 1.013636 ) 0.013636 ​ = 1.516 × 1 0 − 4 per ∘ C . So P = 1.516 .

Physics - Heat & Thermo Question with Solution | TestHub

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