A linear pressure thermometer is calibrated at 60.0 cm Hg for 0 ∘ C and 82.0 cm Hg for 10 0 ∘ C . It reads 73.2 cm Hg. Find temperature in °C. Treat this as an empirical two-point calibration.

C = ( P 100 − P 0 ) 100 ( P − P 0 ) . C = 22 100 ( 73.2 − 60 ) = 6 0 ∘ C .

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PhysicsHeat & ThermoThermal ExpansionEasy2 minQB

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A linear pressure thermometer is calibrated at 60.0 cm Hg for $0^{\circ} C$ and 82.0 cm Hg for $10 0^{\circ} C$ . It reads 73.2 cm Hg. Find temperature in °C. Treat this as an empirical two-point calibration.

Answer:

Solution:

$C = \frac{100 ( P - P _{0} )}{( P _{100} - P _{0} )}$ .

$C = \frac{100 ( 73.2 - 60 )}{22} = 6 0^{\circ} C .$

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

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