The linear expansion coefficient of a rod varies linearly from 10 × 1 0 − 6 per °C at one end to 20 × 1 0 − 6 per °C at the other. A 2.0 m rod is heated by 100°C. Find the increase in length in mm (one decimal).

Effective α = 2 α 1 + α 2 = 15 × 1 0 − 6 . Δ L = 2.0 × 15 × 1 0 − 6 × 100 = 3.0 × 1 0 − 3 m = 3.0 mm.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKinetic Theory of Gases and Gas LawsMedium2 minQB

PhysicsMediumnumerical

The linear expansion coefficient of a rod varies linearly from $10 \times 1 0^{- 6}$ per °C at one end to $20 \times 1 0^{- 6}$ per °C at the other. A 2.0 m rod is heated by 100°C. Find the increase in length in mm (one decimal).

Answer:

3.00

Solution:

Effective

$α = \frac{α _{1} + α _{2}}{2} = 15 \times 1 0^{- 6}$ .

$Δ L = 2.0 \times 15 \times 1 0^{- 6} \times 100 = 3.0 \times 1 0^{- 3}$

m = 3.0 mm.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Kinetic Theory of Gases and Gas Laws

⏱ 2mℹ️ Source: QB

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