The thermal conductivity of a metal is 0.92 cal c m − 1 s − 1 ∘ C − 1 . Find the temperature gradient in ∘ C c m − 1 needed to conduct 23 cal s − 1 c m − 2 in the steady state.

d x d T = K A t Q = 0.92 23 = 2 5 ∘ C c m − 1 . A.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferEasy2 min

PhysicsEasysingle choice

The thermal conductivity of a metal is 0.92 cal $c m^{- 1}$ $s^{- 1}$ $^{\circ}$ $C^{- 1}$ . Find the temperature gradient in $^{\circ}$ C $c m^{- 1}$ needed to conduct 23 cal $s^{- 1}$ $c m^{- 2}$ in the steady state.

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Answer:

Solution:

$\frac{d T}{d x} = \frac{\frac{Q}{A t}}{K} = \frac{23}{0.92} = 2 5^{\circ}$ C $c m^{- 1}$ . A.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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