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PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumnumerical

A particle with period 12 s and amplitude 10 cm has mean position at $x = 0$ . Find the shortest time to go from $x = 8$ cm to $x = 0$ , in s.

Answer:

1.77

Solution:

From $x = 8$ (phase $cos^{- 1} 0.8 = 36.9^{\circ}$ ) to $x = 0$ ( $9 0^{\circ}$ ): $53.1^{\circ}$ . $t = 12 \times \frac{53.1}{360} = 1.77$ s.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

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