Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DMedium2 minQB

PhysicsMediumsingle choice

Passage / Comprehension

Two friends A and B are playing a game of collision of balls and throwing balls from the top of the tower simultaneously as shown in the figure. If the balls collide in air at point P and point O is treated as origin (g = 10 m/s^2).

Distance D between the towers

Options:

Answer:

Solution:

$x_{1} + x_{2} = D \Rightarrow u cos θ t + u^{'} t = D 202 \times \frac{1}{2} t + 20 t = D \Rightarrow 40 t = D$

For y-co-ordinate $300 - {(u sin θ) t + \frac{1}{2} gt^{2}} = 200 - \frac{1}{2} gt^{2}$

$300 - 202 \times \frac{1}{2} t - \frac{1}{2} g t^{2} = 200 - \frac{1}{2} g t^{2} \Rightarrow 100 = 20 t \Rightarrow t = 5$

On using in equation (i) $D = 200 m$ .

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: QB

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