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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGMedium2 minQB

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An ideal gas is taken through a process such that $P V^{2} =$ constant. Then the graph between compressibility (K) and pressure (P) is given by

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Solution:

K = $- \frac{1}{V} \frac{d V}{d P}$ . With $P V^{2} = C$ : $V = C / P$ , $\frac{d V}{d P} = - \frac{C}{2} P^{- 3/2}$ . So $K = \frac{1}{2 P}$ : a rectangular hyperbola in the first quadrant.

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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