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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamicsMedium2 minQB

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The specific heat of a certain monoatomic gas at constant volume is $300 J kg^{- 1} K^{- 1}$ . Calculate the atomic mass (in g/mol). [Take $R = 8.3 J mol^{- 1} K^{- 1}$ ]

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Answer:

Solution:

Monoatomic gas: molar $C_{v} = \frac{3}{2} R = \frac{3}{2} \times 8.3 = 12.45 J mol^{- 1} K^{- 1}$ .

$M = \frac{12.45}{300} kg / mol = 0.0415 kg / mol = 41.5 g / mol .$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics

⏱ 2mℹ️ Source: QB

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