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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGMedium2 minQB

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At room temperature the rms speed of the molecules of a certain diatomic gas is found to be 1930 m/s. The gas is :

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Answer:

Solution:

$v_{rms} = \frac{3 RT}{M} \Rightarrow M = \frac{3 RT}{v ^{2}} = \frac{3 \times 8.314 \times 300}{193 0 ^{2}} \approx 2 \times 1 0^{- 3} kg / mol = 2 g / mol$ , i.e. $H_{2}$ .

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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