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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workMedium2 minQB

PhysicsMediumsingle choice

A block is placed on rough hill. Block is slowly moved over the surface. One of the force of magnitude 'F' is applied perpendicular to the surface and other is always parallel to surface. Select correct statement :

Options:

Answer:

Solution:

$N = mg cos (θ) + F$ for very small displacement

$\int dw = \int - μ [mg cos (θ) + F] \cdot dx = - μ [mgx + Fs]$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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