A refrigerator has a coefficient of performance 4. When 2.4 × 1 0 6 J of work is done on it, what mass of water at 0 ∘ C is turned into ice at 0 ∘ C, in kg (one decimal, L = 3.34 × 1 0 5 J/kg)?

Heat removed = 4 × 2.4 × 1 0 6 = 9.6 × 1 0 6 J. m = 3.34 × 1 0 5 9.6 × 1 0 6 = 28.7 kg.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

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A refrigerator has a coefficient of performance 4. When $2.4 \times 1 0^{6}$ J of work is done on it, what mass of water at $0^{\circ}$ C is turned into ice at $0^{\circ}$ C, in kg (one decimal, $L = 3.34 \times 1 0^{5}$ J/kg)?

Answer:

28.70

Solution:

Heat removed = $4 \times 2.4 \times 1 0^{6} = 9.6 \times 1 0^{6}$ J. $m = \frac{9.6 \times 1 0 ^{6}}{3.34 \times 1 0 ^{5}} = 28.7$ kg.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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