One mole of an ideal gas at 400 K is cooled isochorically until its pressure falls to one-fourth. It is then restored to 400 K by an isobaric process. Find the net heat absorbed in joules (nearest integer).
Answer:
2494
Solution:
$Q = RT (1 - n^{- 1}) = 8.314 \times 400 \times \frac{3}{4} = 2494$ J.

Question

One mole of an ideal gas at 400 K is cooled isochorically until its pressure falls to one-fourth. It is then restored to 400 K by an isobaric process. Find the net heat absorbed in joules (nearest integer).

Answer:

2494

Solution:

$Q = RT (1 - n^{- 1}) = 8.314 \times 400 \times \frac{3}{4} = 2494$ J.

TestHub · Accepted Answer

Q = RT ( 1 − n − 1 ) = 8.314 × 400 × 4 3 ​ = 2494 J.

Physics - Heat & Thermo Question with Solution | TestHub

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