Start Free Mock LoginAlready registered? Login here

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

PhysicsMediumnumerical

A closed vessel of oxygen ( $M = 0.032$ kg/mol, $γ = 1.4$ ) moves at 50 m/s and is suddenly stopped. Find the rise in temperature of the gas in kelvin (two decimals, $R = 8.314$ J $m o l^{- 1}$ $K^{- 1}$ ).

Answer:

1.92

Solution:

$Δ T = \frac{M v ^{2} ( γ - 1 )}{2 R} = \frac{0.032 \times 2500 \times 0.4}{2 \times 8.314} = 1.92$ K.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...