The heat needed to raise 3 mol of a monoatomic gas from 2 0 ∘ C to 12 0 ∘ C at constant pressure is:

Q = 3 × 2 5 R × 100 = 750 R . B.

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PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesEasy2 minQB

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The heat needed to raise 3 mol of a monoatomic gas from $2 0^{\circ}$ C to $12 0^{\circ}$ C at constant pressure is:

Answer:

Solution:

$Q = 3 \times \frac{5}{2} R \times 100 = 750 R$ . B.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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