Water is being boiled in a flat bottom kettle placed on a stove. The area of the bottom is 300 cm² and thickness is 2 mm. If the amount of steam produced is 1 g/min, calculate the difference of temper

Question

Water is being boiled in a flat bottom kettle placed on a stove. The area of the bottom is 300 cm² and thickness is 2 mm. If the amount of steam produced is 1 g/min, calculate the difference of temperature between the inner and outer surfaces of the bottom. The thermal conductivity of the material of kettle $k = 0.5$ cal/s cm °C and latent heat of steam $L = 540$ cal/g.

Answer:

0.01

Solution:

Heat per second = $\frac{1 \times 540}{60} = 9$ cal/s. $Δ T = \frac{Q d}{k A} = \frac{9 \times 0.2}{0.5 \times 300} = 0.012^{\circ}$ C.

TestHub · Accepted Answer

Heat per second = 60 1 × 540 ​ = 9 cal/s. Δ T = k A Q d ​ = 0.5 × 300 9 × 0.2 ​ = 0.012 ∘ C.

Physics - Heat & Thermo Question with Solution | TestHub

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