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Physics - SHM Question with Solution | TestHub

PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumsingle choice

A particle executes SHM of amplitude $A$ and time period $T$ . The distance travelled in the duration its phase changes from $\frac{π}{12}$ to $\frac{5 π}{12}$ is:

Options:

Answer:

Solution:

With $x = A sin ϕ$ : $A (sin 7 5^{\circ} - sin 1 5^{\circ}) = A \times 2 cos 4 5^{\circ} sin 3 0^{\circ} = A / 2$ . No turning point is crossed.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

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