The ends of two rods of different materials, with their lengths, diameters of cross-section and thermal conductivities all in the ratio 1 : 2, are maintained at the same temperature difference. The ra

Question

The ends of two rods of different materials, with their lengths, diameters of cross-section and thermal conductivities all in the ratio 1 : 2, are maintained at the same temperature difference. The rate of flow of heat in the shorter rod is 1 cal $s^{- 1}$ . What is the rate of flow of heat in the larger rod?

Options:

Answer:

B

Solution:

The rate $\propto \frac{k d ^{2}}{l}$ . The larger rod has a factor $\frac{2 \times 4}{2} = 4$ . So 4 cal $s^{- 1}$ . B.

TestHub · Accepted Answer

The rate ∝ l k d 2 ​ . The larger rod has a factor 2 2 × 4 ​ = 4 . So 4 cal s − 1 . B.

Physics - Heat & Thermo Question with Solution | TestHub

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