Physics - SHM Question with Solution | TestHub

In SHM, $v^2={\omega }^2\left(A^2-x^2\right)$, so the v-x graph is an ellipse; read A and $v_{\max }=\omega A$ from it.

Acceleration magnitude at $x=A/2$: $a={\omega }^{2}x=\frac{{\omega }^{2}A}{2}$.

Substituting the graph values gives option B.

Answer: B